Subtraction of two pointers:          Pointer – Pointer

When we subtract two pointers, we get the number of variables of datatype as same as pointer that are stored between the two pointers.

If we use int pointers:

int *x;

int*y;

int i=1;

int y=2;

int d;

Suppose address of i is 3432 and that of j is 4456 and int requires 2 bytes

x=&I;

y=&j;

d= y –x; // answer get is (4456 – 3432)/2 = 1024/2 = 512.

// we divide by 2 as int takes 2 bytes

If we use char pointers:

 char *x;

char*y;

char i;

char y;

char d;

Suppose address of i is 3432 and that of j is 4456 and char requires 1 bytes

x=&I;

y=&j;

d= y –x; // answer get is (4456 – 3432)/1 = 1024/1 = 1024.

// we divide by 1 as char takes 1 bytes